Hi👋SpeedAlgo • Deliberate Practice & Cognitive Ergonomics for Software Engineers

An interactive algorithm mastery and technical interview preparation platform published by Hi👋WebEnterprise. Built for senior and staff software engineers preparing for rigorous coding screens at top tech companies (FAANG/MAMAA).

12 Core Algorithmic Patterns & 168 Practice Problems

  • 1. Two Pointers (9 Paradigms, 32 Problems): Converging pointers, sorted pair sums, container with most water, trapping rain water, 3Sum, plus the Sliding Window and Fast & Slow Pointers paradigms (Floyd cycle detection, monotonic window invariants, longest substrings, minimum window).
  • 2. Binary Search (8 Paradigms, 12 Problems): Monotonic predicate partitioning, boundary searching, rotated arrays, median of two sorted arrays, matrix median on value range.
  • 3. Bit Manipulation (5 Paradigms, 8 Problems): Bitmasking, XOR tricks, counting set bits, subset enumeration via bitmasks.
  • 4. Math & Geometry (5 Paradigms, 10 Problems): Sieve of Eratosthenes, integer/roman conversions, modular arithmetic, geometric simulation.
  • 5. Tree/Graph Depth-First Search (8 Paradigms, 17 Problems): Path sums, lowest common ancestor, tree diameter, subtree serialization, validating BSTs.
  • 6. Tree/Graph Breadth-First Search (4 Paradigms, 11 Problems): Level-order traversals, shortest path, rotting oranges, word ladders.
  • 7. Graphs (6 Paradigms, 14 Problems): Topological sort, cycle detection, Dijkstra, bipartite validation, network delay.
  • 8. Backtracking (5 Paradigms, 13 Problems): Subsets, permutations, combinations, constraint satisfaction, pruning, N-Queens.
  • 9. Dynamic Programming (7 Paradigms, 14 Problems): Memoization vs tabulation, knapsack, coin change, edit distance, longest common subsequence.
  • 10. Heap / Priority Queue (8 Paradigms, 10 Problems): Running medians, top-k elements, interval scheduling, IPO, k-way merges.
  • 11. Advanced Data Structures (5 Paradigms, 13 Problems): Trie, Union-Find, LRU Cache, LFU Cache, Monotonic Stacks.
  • 12. Intervals & Stack / Miscellaneous (7 Paradigms, 14 Problems): Merge intervals, daily temperatures, largest rectangle in histogram, trapping rain water via stack.

4-Stage Deliberate Practice Framework

  1. Stage 1 (Compare & Learn): Multi-language Rosetta Stone contrasting abstract invariants with concrete solutions across Python, C#, Java, TypeScript, C++, Go, and Rust.
  2. Stage 2 (Active Recall): Reconstruct algorithmic template invariants from memory with real-time feedback before looking at solutions.
  3. Stage 3 (Senior SWE AI Mock Coach): Simulated senior mock interview evaluating Big-O space/time tradeoffs, edge cases, and code reviews in Monaco Editor.
  4. Stage 4 (Solve on Your Own): Timed sandbox challenges verified against automated test suites in Python, C#, Java, and TypeScript.

Equipped with SM-2 Spaced Repetition Review Hub, Studio Cockpit workspace layout, and interactive study notes.

Pricing, Access & Commercial Terms

  • Core Curriculum: 100% Free. No credit card required.
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  • BYOK (Bring Your Own Key): Completely free unlimited AI coaching if using your own Gemini/OpenAI API key.
  • Refund & Subscription Policy: No recurring charges, no subscription traps, and no paid paywalls. Free tier provides full learning path.
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Hi👋SpeedAlgo

Invariant-First Algorithmic Mastery

180Items
Theory Context•Two Pointers & Sliding Window
MediumLC 1109

Corporate Flight Bookings (LeetCode 1109)

O(1) Range Updates via Boundary Differential Marking

Target Frequency:GoogleMetaAmazonUber

Given an array of length nnn and a stream of qqq range updates, where each update adds a value vvv to all elements in range [L,R][L, R][L,R], compute the final state of the array after all updates in O(n+q)O(n + q)O(n+q) time.

The Technique Invariant: Instead of iterating through each element from index LLL to RRR for every query (O(q⋅n)O(q \cdot n)O(q⋅n) time), use a Difference Array DDD where D[i]=A[i]−A[i−1]D[i] = A[i] - A[i-1]D[i]=A[i]−A[i−1]:

  • Range modification over [L,R][L, R][L,R] changes only two boundary transitions in the derivative domain: record +v+v+v at entry boundary D[L]D[L]D[L], and −v-v−v at exit boundary D[R+1]D[R + 1]D[R+1].
  • Each range update executes in O(1)O(1)O(1) time.
  • After processing all qqq updates, recover the final modified values across the entire array via a single cumulative prefix sum pass in O(n)O(n)O(n) time. This decouples interval modification time from interval length, reducing total runtime to O(n+q)O(n + q)O(n+q).

Worked Examples

Example 1
Input:bookings = [[1,2,10],[2,3,20],[2,5,25]], n = 5
Output:[10,55,45,25,25]
Explanation: Booking 1 adds 10 to flights 1-2, booking 2 adds 20 to flights 2-3, and booking 3 adds 25 to flights 2-5. Flight 2 gets `10 + 20 + 25 = 55`, flight 3 gets `20 + 25 = 45`, and so on.
Example 2
Input:bookings = [[1,2,10],[2,2,15]], n = 2
Output:[10,25]
Explanation: Flight 1 gets 10. Flight 2 gets `10 + 15 = 25`.

⚖️Formal Constraints & Bounds

  • 1 <= n <= 2 * 104

  • 1 <= bookings.length <= 2 * 104

  • bookings[i].length == 3

  • 1 <= first_i <= last_i <= n

  • 1 <= seats_i <= 104

Deep-Dive & Conceptual Insights

Why It Works & Core Invariant

D[L] \mathrel{+}= v, ; D[R+1] \mathrel{-}= v ⟹ PrefixSum(D) = UpdatedArray — discrete boundary impulses accumulate to constant range shifts.

Real-World Scenario & Production Applications

Cloud load balancers and AWS EC2 auto-scalers use difference arrays to calculate concurrent server capacity from scheduled spot-instance lease windows.

Core Invariant Specification & Code Shape
Archetype Code Shape
Python
1Initialize difference array of size N + 2 with zeros
2For each [start, end, val]: diff[start] += val; diff[end + 1] -= val
3Compute running prefix sum to reconstruct final array in O(N)

Target: Corporate Flight Bookings (LeetCode 1109). 1-indexed buffer with +2 padding prevents index out-of-bounds on last + 1 cancellation updates during range sweeps.

Boundary Model: Telescoping Delta Boundaries [L, R + 1)

Add +V at start index L. Subtract -V at cancellation index R + 1 (if R + 1 < N).

Loop Invariant Termination

D[L] += v; if R + 1 < n: D[R + 1] -= v; curr = 0; for i in range(n): curr += D[i]; res[i] = curr

Conceptual Narrative

The Flash of Genius: Applying Q range updates [L, R, +V] naively costs O(Q × N). By transforming the array into its discrete derivative D[i] = A[i] - A[i-1], each range update reduces to exactly two boundary modifications: D[L] += V and D[R+1] -= V. Reconstructing via a prefix sum takes O(Q + N) total time.

The Mental Model Analogy: The Highway Toll Highway On-Ramp and Off-Ramp Counters

Imagine managing a 100-mile stretch of turnpike divided into 1-mile segments. Every day, 50,000 cars enter and exit at various ramps. A delivery van enters at Mile 10 and exits at Mile 40, adding 1 vehicle to every mile in [10, 40]. If a highway engineer had to drive out and repaint the traffic count sign on every single mile from 10 to 40 for all 50,000 trips, they would paint over 1.5 billion numbers! Instead, a brilliant traffic engineer installs automated sensors only at the ramps: When a car enters at Mile 10, write '+1' at Mile 10. When it leaves at Mile 40, write '-1' at Mile 41! At the end of the day, a single automated sensor car drives from Mile 0 to Mile 100, maintaining a running sum. At Mile 10, the running sum jumps up by 1. At Mile 41, the running sum drops by 1. With just 2 numbers recorded per trip, the entire traffic profile for all 100 miles is calculated in one smooth pass!

  • Pitfall: A difference array is the discrete derivative: diff[i] = arr[i] - arr[i - 1].

  • Pitfall: Adding +val at index 'start' cascades through all subsequent prefix sums.

  • Pitfall: Adding -val at index 'end + 1' cancels the increment for all elements beyond the interval.

Senior SWE Reasoning Architecture

4-Phase Thought Process Model

Senior SWE thought process architecture for The Difference Array (Range Derivative).

Pattern Recognition Signals

The 10-second spot

The input provides QQQ range additions on an array of size NNN, and requires the finalized array state at the end. Because queries are offline (no intermediate reads), a difference array is optimal.

Formulating the Predicate & Invariants

Turning intuition into a boolean rule

Allocate a difference buffer of size N+2N + 2N+2 to safely accommodate 1-indexed boundaries and R+1R + 1R+1 exit cancellations without conditional branches.

Silent Failure Traps & Edge Cases

Where confident candidates still lose points

  • Accumulation: A[i]=∑j=0iD[j]A[i] = \sum_{j=0}^{i} D[j]A[i]=∑j=0i​D[j].

  • In-place reuse: Overwrite diff array directly to avoid allocating a separate result buffer.

The 60-Second Interview Pitch

Say this out loud before you type a single line

Verify edge cases: R=NR = NR=N (exit cancellation falls outside array and is ignored), single element intervals [i,i][i, i][i,i], and multiple overlapping intervals.

Applying Q range updates [L, R, +V] naively costs O(Q × N). By transforming the array into its discrete derivative D[i] = A[i] - A[i-1], each range update reduces to exactly two boundary modifications: D[L] += V and D[R+1] -= V. Reconstructing via a prefix sum takes O(Q + N) total time.

Big-O Invariant Derivation

Complexity & Mathematical Proof

TIME COMPLEXITY

O(Q + N)

Processing each of the Q range update queries performs exactly two array writes (diff[L] += V and diff[R+1] -= V), taking O(1) time per query, totaling O(Q). The subsequent prefix sum pass iterates from index 0 to N - 1, performing one addition per element in O(N). The total time complexity is strictly O(Q + N), which is linear.

SPACE COMPLEXITY

O(N)

The difference array requires N + 1 integer slots to hold the delta impulses. If modifying an existing array in-place, auxiliary space is O(1); if allocating a new difference array, space is strictly O(N).

Formal Recurrence Relation

lim⁡k→∞N2k=1  ⟹  2k=N  ⟹  k=log⁡2N\lim_{k \to \infty} \frac{N}{2^k} = 1 \implies 2^k = N \implies k = \log_2 Nlimk→∞​2kN​=1⟹2k=N⟹k=log2​N

Processing each of the Q range update queries performs exactly two array writes (diff[L] += V and diff[R+1] -= V), taking O(1) time per query, totaling O(Q). The subsequent prefix sum pass iterates from index 0 to N - 1, performing one addition per element in O(N). The total time complexity is strictly O(Q + N), which is linear.

Pointer Invariant Transition Progression

Pointer Invariant Transition Progression
Synthesizing vector architecture diagram...
Staff+ Engineering Perspective

Senior SWE Deconstruction & Hardware Caveats

ARCHITECTURAL SIGNALS & INTERVIEW TRIGGERS

Immediately identifies that batch offline range updates do not require a Segment Tree or Fenwick Tree. • Allocates N + 1 or N + 2 buffer size to prevent out-of-bounds writes on R + 1 cancellations. • Explains the mathematical telescoping sum proof clearly. • Demonstrates knowledge of 2D extensions: 4-corner difference updates for grid manipulations.

CONSTRAINTS & BOUNDS

1 <= n <= 2 * 104. 1 <= bookings.length <= 2 * 104. bookings[i].length == 3. 1 <= first_i <= last_i <= n. 1 <= seats_i <= 104

FAANG PRODUCTION TRAPS & EDGE CASES

In video streaming and CDN rate limiting, difference arrays track concurrent bandwidth allocations across millisecond timestamps. • Flight booking and hotel reservation engines use difference arrays to verify seat and room inventory across reservation dates in bulk.

Core Algorithmic State Invariants

1. Monotonic Window Expansion

The right pointer advances forward, absorbing the incoming element into the running aggregation state (frequency map, sum, or set).

2. Window Validity & Contraction Invariant

When window constraints are violated (or while valid when seeking minimal length), the left pointer increments to evict elements and restore the required invariant.

3. Amortized Linear Termination

Because each element enters and exits the window at most once, total operations across both pointers are bounded by 2N, guaranteeing strictly linear O(N) execution.

Theory Context•Two Pointers & Sliding Window
MediumLC 1109

Corporate Flight Bookings (LeetCode 1109)

O(1) Range Updates via Boundary Differential Marking

Target Frequency:GoogleMetaAmazonUber

Given an array of length nnn and a stream of qqq range updates, where each update adds a value vvv to all elements in range [L,R][L, R][L,R], compute the final state of the array after all updates in O(n+q)O(n + q)O(n+q) time.

The Technique Invariant: Instead of iterating through each element from index LLL to RRR for every query (O(q⋅n)O(q \cdot n)O(q⋅n) time), use a Difference Array DDD where D[i]=A[i]−A[i−1]D[i] = A[i] - A[i-1]D[i]=A[i]−A[i−1]:

  • Range modification over [L,R][L, R][L,R] changes only two boundary transitions in the derivative domain: record +v+v+v at entry boundary D[L]D[L]D[L], and −v-v−v at exit boundary D[R+1]D[R + 1]D[R+1].
  • Each range update executes in O(1)O(1)O(1) time.
  • After processing all qqq updates, recover the final modified values across the entire array via a single cumulative prefix sum pass in O(n)O(n)O(n) time. This decouples interval modification time from interval length, reducing total runtime to O(n+q)O(n + q)O(n+q).

Worked Examples

Example 1
Input:bookings = [[1,2,10],[2,3,20],[2,5,25]], n = 5
Output:[10,55,45,25,25]
Explanation: Booking 1 adds 10 to flights 1-2, booking 2 adds 20 to flights 2-3, and booking 3 adds 25 to flights 2-5. Flight 2 gets `10 + 20 + 25 = 55`, flight 3 gets `20 + 25 = 45`, and so on.
Example 2
Input:bookings = [[1,2,10],[2,2,15]], n = 2
Output:[10,25]
Explanation: Flight 1 gets 10. Flight 2 gets `10 + 15 = 25`.

⚖️Formal Constraints & Bounds

  • 1 <= n <= 2 * 104

  • 1 <= bookings.length <= 2 * 104

  • bookings[i].length == 3

  • 1 <= first_i <= last_i <= n

  • 1 <= seats_i <= 104

Deep-Dive & Conceptual Insights

Why It Works & Core Invariant

D[L] \mathrel{+}= v, ; D[R+1] \mathrel{-}= v ⟹ PrefixSum(D) = UpdatedArray — discrete boundary impulses accumulate to constant range shifts.

Real-World Scenario & Production Applications

Cloud load balancers and AWS EC2 auto-scalers use difference arrays to calculate concurrent server capacity from scheduled spot-instance lease windows.

Core Invariant Specification & Code Shape
Archetype Code Shape
Python
1Initialize difference array of size N + 2 with zeros
2For each [start, end, val]: diff[start] += val; diff[end + 1] -= val
3Compute running prefix sum to reconstruct final array in O(N)

Target: Corporate Flight Bookings (LeetCode 1109). 1-indexed buffer with +2 padding prevents index out-of-bounds on last + 1 cancellation updates during range sweeps.

Boundary Model: Telescoping Delta Boundaries [L, R + 1)

Add +V at start index L. Subtract -V at cancellation index R + 1 (if R + 1 < N).

Loop Invariant Termination

D[L] += v; if R + 1 < n: D[R + 1] -= v; curr = 0; for i in range(n): curr += D[i]; res[i] = curr

Conceptual Narrative

The Flash of Genius: Applying Q range updates [L, R, +V] naively costs O(Q × N). By transforming the array into its discrete derivative D[i] = A[i] - A[i-1], each range update reduces to exactly two boundary modifications: D[L] += V and D[R+1] -= V. Reconstructing via a prefix sum takes O(Q + N) total time.

The Mental Model Analogy: The Highway Toll Highway On-Ramp and Off-Ramp Counters

Imagine managing a 100-mile stretch of turnpike divided into 1-mile segments. Every day, 50,000 cars enter and exit at various ramps. A delivery van enters at Mile 10 and exits at Mile 40, adding 1 vehicle to every mile in [10, 40]. If a highway engineer had to drive out and repaint the traffic count sign on every single mile from 10 to 40 for all 50,000 trips, they would paint over 1.5 billion numbers! Instead, a brilliant traffic engineer installs automated sensors only at the ramps: When a car enters at Mile 10, write '+1' at Mile 10. When it leaves at Mile 40, write '-1' at Mile 41! At the end of the day, a single automated sensor car drives from Mile 0 to Mile 100, maintaining a running sum. At Mile 10, the running sum jumps up by 1. At Mile 41, the running sum drops by 1. With just 2 numbers recorded per trip, the entire traffic profile for all 100 miles is calculated in one smooth pass!

  • Pitfall: A difference array is the discrete derivative: diff[i] = arr[i] - arr[i - 1].

  • Pitfall: Adding +val at index 'start' cascades through all subsequent prefix sums.

  • Pitfall: Adding -val at index 'end + 1' cancels the increment for all elements beyond the interval.

Senior SWE Reasoning Architecture

4-Phase Thought Process Model

Senior SWE thought process architecture for The Difference Array (Range Derivative).

Pattern Recognition Signals

The 10-second spot

The input provides QQQ range additions on an array of size NNN, and requires the finalized array state at the end. Because queries are offline (no intermediate reads), a difference array is optimal.

Formulating the Predicate & Invariants

Turning intuition into a boolean rule

Allocate a difference buffer of size N+2N + 2N+2 to safely accommodate 1-indexed boundaries and R+1R + 1R+1 exit cancellations without conditional branches.

Silent Failure Traps & Edge Cases

Where confident candidates still lose points

  • Accumulation: A[i]=∑j=0iD[j]A[i] = \sum_{j=0}^{i} D[j]A[i]=∑j=0i​D[j].

  • In-place reuse: Overwrite diff array directly to avoid allocating a separate result buffer.

The 60-Second Interview Pitch

Say this out loud before you type a single line

Verify edge cases: R=NR = NR=N (exit cancellation falls outside array and is ignored), single element intervals [i,i][i, i][i,i], and multiple overlapping intervals.

Applying Q range updates [L, R, +V] naively costs O(Q × N). By transforming the array into its discrete derivative D[i] = A[i] - A[i-1], each range update reduces to exactly two boundary modifications: D[L] += V and D[R+1] -= V. Reconstructing via a prefix sum takes O(Q + N) total time.

Big-O Invariant Derivation

Complexity & Mathematical Proof

TIME COMPLEXITY

O(Q + N)

Processing each of the Q range update queries performs exactly two array writes (diff[L] += V and diff[R+1] -= V), taking O(1) time per query, totaling O(Q). The subsequent prefix sum pass iterates from index 0 to N - 1, performing one addition per element in O(N). The total time complexity is strictly O(Q + N), which is linear.

SPACE COMPLEXITY

O(N)

The difference array requires N + 1 integer slots to hold the delta impulses. If modifying an existing array in-place, auxiliary space is O(1); if allocating a new difference array, space is strictly O(N).

Formal Recurrence Relation

lim⁡k→∞N2k=1  ⟹  2k=N  ⟹  k=log⁡2N\lim_{k \to \infty} \frac{N}{2^k} = 1 \implies 2^k = N \implies k = \log_2 Nlimk→∞​2kN​=1⟹2k=N⟹k=log2​N

Processing each of the Q range update queries performs exactly two array writes (diff[L] += V and diff[R+1] -= V), taking O(1) time per query, totaling O(Q). The subsequent prefix sum pass iterates from index 0 to N - 1, performing one addition per element in O(N). The total time complexity is strictly O(Q + N), which is linear.

Pointer Invariant Transition Progression

Pointer Invariant Transition Progression
Synthesizing vector architecture diagram...
Staff+ Engineering Perspective

Senior SWE Deconstruction & Hardware Caveats

ARCHITECTURAL SIGNALS & INTERVIEW TRIGGERS

Immediately identifies that batch offline range updates do not require a Segment Tree or Fenwick Tree. • Allocates N + 1 or N + 2 buffer size to prevent out-of-bounds writes on R + 1 cancellations. • Explains the mathematical telescoping sum proof clearly. • Demonstrates knowledge of 2D extensions: 4-corner difference updates for grid manipulations.

CONSTRAINTS & BOUNDS

1 <= n <= 2 * 104. 1 <= bookings.length <= 2 * 104. bookings[i].length == 3. 1 <= first_i <= last_i <= n. 1 <= seats_i <= 104

FAANG PRODUCTION TRAPS & EDGE CASES

In video streaming and CDN rate limiting, difference arrays track concurrent bandwidth allocations across millisecond timestamps. • Flight booking and hotel reservation engines use difference arrays to verify seat and room inventory across reservation dates in bulk.

Core Algorithmic State Invariants

1. Monotonic Window Expansion

The right pointer advances forward, absorbing the incoming element into the running aggregation state (frequency map, sum, or set).

2. Window Validity & Contraction Invariant

When window constraints are violated (or while valid when seeking minimal length), the left pointer increments to evict elements and restore the required invariant.

3. Amortized Linear Termination

Because each element enters and exits the window at most once, total operations across both pointers are bounded by 2N, guaranteeing strictly linear O(N) execution.

Rosetta Dual-Monaco Comparison
Python 3
CANONICAL INVARIANT TEMPLATE
Loading...
CONCRETE: CORPORATE FLIGHT BOOKINGS (LEETCODE 1109)
T = O(Q + N)S = O(N)
Loading...
Pattern Implementation Mapping TableCanonical Invariant ⟷ Concrete Code ⟷ Engineering Rationale
Canonical InvariantConcrete CodeEngineering Rationale
diff = [0] * (n + 2)diff = [0] * (n + 2)1-indexed buffer with +2 padding prevents index out-of-bounds on last + 1 cancellation updates during range sweeps.
diff[start] += delta; diff[end + 1] -= deltadiff[first] += seats diff[last + 1] -= seatsBoundary delta injection: turns an expensive O(N) range mutation into two instantaneous O(1) index updates.
curr += diff[i]; result[i - 1] = currcurr += diff[i] result[i - 1] = currPrefix integration sweep: running accumulator propagates range impacts across indices until cancelled by the negative delta.
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